Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.


A compression spring with a spring constant of 200 N/m catches a ball that's falling with
kinetic energy of 0.5 J. How far will the spring compress to stop the ball?
Pls help It would be great if someone can show the steps too thank u


Sagot :

fieryanswererft

Answer:

distance of compression: 0.07071 m

Explanation:

[tex]\sf energy = \dfrac{1}{2} kx^2[/tex]

[tex]\rightarrow \sf 0.5= \dfrac{1}{2} (200)x^2[/tex]

[tex]\rightarrow \sf 0.5= (100)x^2[/tex]

[tex]\rightarrow \sf 5\ *\ 10^{-3}= x^2[/tex]

[tex]\rightarrow \sf x = \sqrt{5\ *\ 10^{-3}}[/tex]

[tex]\rightarrow \sf x =0.07071 \ m[/tex]

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.