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A compression spring with a spring constant of 200 N/m catches a ball that's falling with
kinetic energy of 0.5 J. How far will the spring compress to stop the ball?
Pls help It would be great if someone can show the steps too thank u

Sagot :

fieryanswererft

Answer:

distance of compression: 0.07071 m

Explanation:

[tex]\sf energy = \dfrac{1}{2} kx^2[/tex]

[tex]\rightarrow \sf 0.5= \dfrac{1}{2} (200)x^2[/tex]

[tex]\rightarrow \sf 0.5= (100)x^2[/tex]

[tex]\rightarrow \sf 5\ *\ 10^{-3}= x^2[/tex]

[tex]\rightarrow \sf x = \sqrt{5\ *\ 10^{-3}}[/tex]

[tex]\rightarrow \sf x =0.07071 \ m[/tex]

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