jayikemp
Answered

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Given the function h of x equals 8 times the cube root of x minus 6 end root plus 16, what is the x-intercept of the function?

–6
–2
2
16

Sagot :

MrRoyal

The x-intercept of the function h(x) is when the function h(x) = 0

The x-intercept of the function is -2

How to determine the x-intercept?

From the question, the function is given as:

[tex]h(x) = 8 * \sqrt[3]{x - 6} + 16[/tex]

Set the function h(x) to 0, to calculate the x-intercept

[tex]8 * \sqrt[3]{x - 6} + 16= 0[/tex]

Subtract 16 from both sides of the equation

[tex]8 * \sqrt[3]{x - 6} +=-16[/tex]

Divide through by 8

[tex]\sqrt[3]{x - 6} =-2[/tex]

Take the cube of both sides

[tex]x - 6 =-8[/tex]

Add 6 to both sides

[tex]x =-2[/tex]

Hence, the x-intercept of the function is -2

Read more about x-intercept at:

https://brainly.com/question/3951754

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