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The instantaneous rate of change of g with respect to x at x = π/3 is 1/2.
How to determine the instantaneous rate of change of a given function
The instantaneous rate of change at a given value of [tex]x[/tex] can be found by concept of derivative, which is described below:
[tex]g(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}[/tex]
Where [tex]h[/tex] is the difference rate.
In this question we must find an expression for the instantaneous rate of change of [tex]g[/tex] if [tex]f(x) = \sin x[/tex] and evaluate the resulting expression for [tex]x = \frac{\pi}{3}[/tex]. Then, we have the following procedure below:
[tex]g(x) = \lim_{h \to 0} \frac{\sin (x+h)-\sin x}{h}[/tex]
[tex]g(x) = \lim_{h \to 0} \frac{\sin x\cdot \cos h +\sin h\cdot \cos x -\sin x}{h}[/tex]
[tex]g(x) = \lim_{h \to 0} \frac{\sin h}{h}\cdot \lim_{h \to 0} \cos x[/tex]
[tex]g(x) = \cos x[/tex]
Now we evaluate [tex]g(x)[/tex] for [tex]x = \frac{\pi}{3}[/tex]:
[tex]g\left(\frac{\pi}{3} \right) = \cos \frac{\pi}{3} = \frac{1}{2}[/tex]
The instantaneous rate of change of g with respect to x at x = π/3 is 1/2. [tex]\blacksquare[/tex]
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The instantaneous rate of change of g with respect to x at x = π/3 is 1/2.
What is the instantaneous rate of change?
The instantaneous rate of change is the change in the rate at a particular instant, and it is the same as the change in the derivative value at a specific point.
The instantaneous rate of change is given by the following formula;
[tex]\rm g(x)=lim_{h\rightarrow 0}\dfrac{f(x+h)-f(x)}{h}[/tex]
The given function is;
[tex]\rm f(x)=sinx[/tex]
The function is also written as;
[tex]\rm g(x)=lim_{h\rightarrow 0}\dfrac{sin(x+h)-sin(x)}{h}\\\\g(x)=lim_{h\rightarrow 0}\dfrac{sinx cosh +cosx sinh-sinx}{h}\\\\g(x)=lim_{h\rightarrow 0}\dfrac{sinh}{h}. \ lim_{h\rightarrow 0} cosx\\\\g(x)=cosx[/tex]
Substitute the value of x in the function
[tex]\rm g(\pi /3)= cos(\pi /3)=1/2\\[/tex]
Hence, the instantaneous rate of change of g with respect to x at x = π/3 is 1/2.
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https://brainly.com/question/11606037
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