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Sagot :
The equation that shows the relationship between X₁ and X₂ in the springs is X₁ = 4X₂.
How to compute the equation?
From the complete question, for case I, the two springs stretch up to the distance of X₁. Therefore, f = mg = kx₁.
For case 2, f = mg = kx₂.
Therefore, we'll equate the equations. This will be:
Kx₁ = Kx₂
(K/2)x₁ = (2k)x₂
K(x₁/2) = k(2x₂)
X₁/2 = 2x₂
X1 = 2 × 2x₂
X₁ = 4X₂.
In conclusion, X₁ = 4X₂.
Learn more about equations on:
https://brainly.com/question/2972832
X₁ = 4X₂ is the equation that shows the connection between X₁ and X₂ in the springs.
What is spring force?
The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is
F = kx
For case 1;
f=mg=kx₁
For case 2;
f=mg=kx₂
After equating the equation we get;
[tex]\rm Kx_1 = Kx_2 \\\\ \frac{K}{2}x_1 = (2k)x_2 = k(2x_2) \\\\ \frac{x_1}{2} =2x_2\\\\ x_1 = 4x_2[/tex]
Hence X₁ = 4X₂ is the equation that shows the connection between X₁ and X₂ in the springs.
To learn more about the spring force refer to the link;
https://brainly.com/question/4291098
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