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Using standard thermodynamic data at 298k, calculate the free energy change when 2. 34 moles of nh3(g) react at standard conditions

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okpalawalter8

For a thermodynamic data at 298k, when 2. 34 moles of nh3(g) react at standard conditions, the free energy change is mathematically given as

dG'−213.174KJ

What is the free energy change?

Generally, the equation for the Chemical Reaction   is mathematically given as

HCL+NH3----->NH4Cl

Therefore

dG=-202.9-[-16.5+(95.3)]

dG=-91.1KJ/mol

In conclusion, For 2.34 moles

dG'=-91.1KJ/mol*2.34

dG'−213.174KJ

Read more about Chemical Reaction

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The free energy change when 2.34 moles of NH₃(g) react at standard conditions is -213.174 kJ.

How do we calculate free energy change?

Free energy change of any chemical reaction will be calculated by using the following chemical reaction:

ΔG = Free energy of products - Free energy of reactants

Given chemical reaction is:

NH₃ + HCl → NH₄Cl

From the stoichiometry of the reaction it is clear that same moles of ammonium chloride is produced by the same moles of ammonia & hydrochloric acid.

Free enrgy of NH₄Cl = -202.9 kJ/mol

Free enrgy of NH₃ = -16.5 kJ/mol

Free enrgy of HCl = 95.3 kJ/mol

On putting values in the above equation, we get

ΔG = -202.9-[-16.5+(95.3)]

ΔG = -91.1KJ/mol

For 2.34 moles, ΔG will be:

ΔG = (2.34)(-91.1) = -213.174 kJ

Hence required amount of free eenrgy is -213.174 kJ.

To know more about free energy, visit the below link:

https://brainly.com/question/9063838

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