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The standard change in free energy is -35.76 kJ/mol. Values of standard free energy are obtained from thermodynamic tables.
What is the standard change in free energy?
The standard change in free energy can be obtained using the relation;
ΔG°= ΔH° - TΔS
When;
ΔH°f(HI) = 26.466 kJ/mol
ΔH°f(H2) = 0 kJ/mol
ΔH°f(I2) = 0 kJ/mol
ΔS°f(HI) = 221.63 J/K/mol
ΔS°f(H2) = 145.64 J/K/mol
ΔS°f(I2) = 0 J/K/mol
Hence;
ΔH°freaction = [ 2(26.466)] - 0
= 52.932 kJ/mol
ΔS°freaction = [2(221.63 ) ] - [145.64 + 0]
= 443.26 - 145.64 = 297.62 J/K/mol
ΔG°= 52.932 * 10^3 - [298 * 297.62 ]
ΔG°= -35.76 kJ/mol
The standard change in free energy is -35.76 kJ/mol.
Learn more about change in free energy: https://brainly.com/question/14143095
The change in free energy for the given chemical reaction between hydrogen and iodine gas is -31.068 kJ/mol.
How do we calculate the free energy change?
Free energy change of any reaction will be calculated by using the below equation:
ΔG° = ΔH° - TΔS, where
ΔH° = change in enthalpy
T = absolute temperature = 298K
ΔS = change in entropy
Change in any quantity during the reaction will be find out by substracting the reactant values from product values.
Given chemical reaction is:
H₂(g) + I₂(g) → 2HI(g)
ΔH° = 2(26.466)] - 0 = 52.932 kJ/mol
ΔS = [2(206.6) ] - [131 + 0] = 413.2 - 131 = 282.2 J/K.mol = 0.282 kJ/K.mol
On putting values on above equation, we get
ΔG° = 52.932 - (298)(0.282) = -31.068 kJ/mol
Hence required free enrgy is -31.068 kJ/mol.
To know more about free energy change, visit the below link:
https://brainly.com/question/7600523
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