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Sagot :
Answer:
A reaction is second order with respect to a reactant.
Rate =k[A]
2
(i) If the concentration of the reactant is doubled, the rate of reaction becomes 4 times .
(ii) If the concentration of the reactant is reduced to half, the rate of reaction becomes one fourth.
Explanation:
If a reaction is second-order with respect to a particular reactant, when the concentration of that reactant is increased by a factor of 4, the reaction rate will increased by factor 16.
How do we calculate the rate of second order reaction?
Rate of the second order reaction will depends on the concentrations of one second-order reactant or two first-order reactants as:
Rate(1) = k[A]²
If the concentration of reactant becomes 4 times the initial concentration then rate will be:
Rate = k[4A]²
Rate(2) = 16k[A]²
Rate(2) = 16Rate(1)
Hence rate will increased by 16 times.
To know more about second order reaction, visit the below link:
https://brainly.com/question/17217385
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