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Sagot :
The magnitude of the electrical force between the two identical electrical charges is 8.98755 × 10⁹N.
Given the data in the question;
- Single charge each with; [tex]q_1\ and\ q_2[/tex] [tex]= 1C[/tex]
- Distance between; [tex]r = 1m[/tex]
- Electric force between; [tex]F = \ ?[/tex]
Coulomb's law
Coulomb's law states "that the force between two electrical charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them".
It is expressed as;
[tex]F = k\frac{q_1q_2}{r^2}[/tex]
Here, [tex]q_1\ and\ q_2[/tex] are the two electrical charges, r is the distance between them and k is the Coulomb constant ( [tex]k = 8.98755*10^9 kgm^3/s^2C^2[/tex])
To determine the electrical force between the two charges, we substitute our values into the expression above.
[tex]F = k\frac{q_1q_2}{r^2}\\\\F = (8.98755*10^9 kgm^3/s^2C^2)*\frac{(1C)(1C)}{(1m)^2}\\\\F = (8.98755*10^9 kgm^3/s^2C^2)*\frac{1C^2}{1m^2}\\\\F = 8.98755*10^9 kgm/s^2\\\\F = 8.98755*10^9 N[/tex]
Therefore, the magnitude of the electrical force between the two identical electrical charges is 8.98755 × 10⁹N.
Learn more about coulomb's law: brainly.com/question/506926
The magnitude of the electrical force between the two charges is 8.987×10⁹ N.
What is coulomb's law?
As per the coulomb's law, the electrical force between any two charges separated by a distance of r is given by the formula,
[tex]F = k\dfrac{q_1q_2}{r^2}[/tex]
Given that the value of q₁ and q₂ is 1 coulomb, while the distance between them is 1 meter. Also, the value of k is 8.987×10⁹ N·m²·C⁻², therefore, the force can be written as,
[tex]F = k\dfrac{q_1q_2}{r^2}\\\\F = (8.987 \times 10^{9}) \times (\dfrac{1 \times 1}{1^2})\\\\F= 8.987 \times 10^{9}\rm\ N[/tex]
Hence, the magnitude of the electrical force between the two charges is 8.987×10⁹ N.
Learn more about Coulomb's Law:
https://brainly.com/question/506926
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