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A bicycle wheel of radius 40. 0 cm and angular velocity of 10. 0 rad/s starts accelerating at 80. 0 rad/s2. What is the centripetal acceleration of the wheel at this time point?

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onyebuchinnaji

The magnitude of the centripetal acceleration of the bicycle wheel is 40 m/s².

Centripetal acceleration of the wheel

The centripetal acceleration of the bicycle wheel is the inward or radial acceleration of the bicycle on the circular path.

The magnitude of the centripetal acceleration of the bicycle wheel is calculated as follows;

a = ω²r

where;

ω is angular speed

r is the radius of the circular path

a = (10)² x 0.4

a = 40 m/s²

Thus, the magnitude of the centripetal acceleration of the bicycle wheel is 40 m/s².

Learn more about centripetal acceleration  here: https://brainly.com/question/79801

The acceleration of a body travelling in a circular route is known as centripetal acceleration.  The centripetal acceleration of the wheel at this time point is 40 m/sec².

What is centripetal acceleration?

The acceleration of a body travelling in a circular route is known as centripetal acceleration. It is given by the formula,

[tex]a_c = \dfrac{v^2}{r} = \omega^2 r[/tex]

The centripetal acceleration of the wheel with angular velocity 10 rad/sec and velocity 40cm (0.4 m) can be written as,

[tex]a_c = \omega ^2\times r\\\\a_c = (10)^2\times 0.4\\\\a_c = 40\rm\ m/sec^2[/tex]

Hence, the centripetal acceleration of the wheel at this time point is 40 m/sec².

Learn more about Centripetal acceleration:

https://brainly.com/question/14465119

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