Answered

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A uniform rod of length l and mass m is pivoted around a line perpindicular to the rod at location l/3

Sagot :

Answer:

I for a rod about its center is I = M L^2 / 12

A = L (1/2 - 1/3) = L / 6     distance from middle to location L/3

A^2 = L^2 / 36

I = M L^2 (1/12 + 1/36) = M L^2 (4 / 36) = M L^2 / 9

I about given location by parallel axis theorem

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