Answer:
88mm^2
Sorry for not answering it early I know this answer is probably useless for you now
Step-by-step explanation:
Ok, suppose we were to divide this figure into two parts figure 1 & 2
like this... the picture is goven above
So, we can clearly see that figure 1 is a square as it has equal dimensions
and figure 2 is a rectangle because it should given in ur question but this is the only way to find out the area
So in figure 1 the dimensions are already give that the square is 8mm and on the other hand in figure 2 it is a rectangle, here only length is given - 6mm but width is not given. To find out the width it's simple, since the base of figure 1and2 is 12mm and the base of figure 1 is 8cm we can subtract it to get there rest of the base that is the base of figure 2.
So we get,
Base of figure 2 = Total base - Base of figure 1 = 12mm - 8mm = 4mm
Now since we have the dimensions, we only have to find the area of those two figures and add both areas to get the total are of the whole figure.
Area of figure 1
Area of square = side*side = 8*8 = 64mm^2
Area of figure 2
Area of rectangle = length*breadth = 4*6 = 24mm^2
Total area of the figures
Area of figure 1 + Area of figure 2 = 64mm^2+ 24mm^2 = 88mm^2
