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Smokers: Out of 780 smokers, 376 have been divorced.
Non-smokers: Out of 2855 non-smokers, 902 have been divorced.

a) Find the 95% confidence interval for the proportion of smokers that have been divorced.

b) Find the 95% confidence interval for the proportion of non-smokers that have been divorced.

c) What do the results above indicate about smoking and divorce?

Sagot :

okpalawalter8

For statictics of Out of 780 smokers, 376 have been divorced, Non-smokers: Out of 2855 non-smokers, 902 have been divorced, the 95% confidence interval for smokers and non-smokers is mathematically given as

  • 95% confidence interval = (0.5352, 0.4462)
  • 95% confidence interval = (0.3424, 0.2894)
  • 53% increased risk of divorce for smokers.

What is the 95% confidence interval for smokers and non-smokers?

Generally, the equation for the Confidence interval is mathematically given as

p ± Z/2[p(1-p)]/n

Where

Z1/2=1-(0.05/2)

Z1/2=0.975

Read z table we have

Z score= 1.96

Hence

0.4907 ± 1.96 (0.4907)(1-0.4907)/485

0.4907±0.0445

Therefore

95% confidence interval = (0.5352, 0.4462)

b)

Z1/2 = 1- (0.05/2)

Z1/2 = 0.975

Z score= 1.96

0.3159 ± 1.96 (0.3159)(1-0.3159)/1184

0.3159±0.0265

Thereofore

95% confidence interval = (0.3424, 0.2894)

c)

In conclusion, The 95% confidence interval helps us read that 53% increased risk of divorce for smokers.

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