For ksp of silver sulfate (ag2so4) at 1. 2 ✕ 10-5, the solubility of silver sulfate is mathematically given as
x = 5.26*10^{-4}
Generally, the equation for the Chemical reaction is mathematically given as
Ag2SO4 ⇄ 2Ag+ + SO4 2-
Therefore
Ksp = [Ag+ ]2 *[SO4 2-]
1.2*10-5 = ( 0.15 +2x)2*(x)
x = 5.26*10^{-4}
In conclusion, the solubility of silver sulfate is
x = 5.26*10^{-4}
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If the ksp of silver sulfate (ag2so4) at 1.2 × 10⁻⁵, the solubility of silver sulfate is 5.26 × 10⁽⁻⁴⁾.
ksp value determines the equilibrium between the solids and its respective ions in a solution.
The reaction is [tex]\rm Ag_2SO_4 \leftrightharpoons 2Ag+ + SO_4^2-[/tex]
The ksp pf silver sulfate is 1.2 × 10⁻⁵
Tho calculate the solubility?
Putting the values in the equation
[tex]\rm Ksp = [Ag^+ ]^2 \times [SO_4^ 2^-]\\\\1.2\times 10^-^5 = ( 0.15 +2x)2\times (x)\\x = 5.26\times 10^{-4}[/tex]
Thus, the solubility of silver sulfate is 5.26 × 10⁽⁻⁴⁾.
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