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Since the magnetic flux through a coil of wire containing two loops changes at a constant rate from -58 wb to 38 wb in 0. 34 s, the emf induced in the coil is -5.65 V
Induced emf in coil
The induced emf in the coil is given by ε = -NΔΦ/Δt where
- ΔΦ = change in magnetic flux Φ₂ - Φ₁ where
- Φ₁ = initial magnetic flux = -58 Wb and
- Φ₂ = final magnetic flux = 38 Wb and and
- Δt = change in time = t₂ - t₁ where
- t₁ = initial time = 0 s and
- t₂ = final time = 34 sand
- N = number of loops of coil = 2
Since ε = -NΔΦ/Δt
ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)
Substituting the values of the variables into the equation, we have
ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)
ε = -2(38 Wb - (-58 Wb))/(34 s - 0 s)
ε = -2(38 Wb + 58 Wb)/(34 s - 0 s)
ε = -2(96 Wb)/34 s
ε = -192 Wb/34 s
ε = -5.65 Wb/s
ε = -5.65 V
So, the emf induced in the coil is -5.65 V
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The electrical action generated by a non-electrical source, measured in volts. The emf induced in the coil is -564.7 V.
What is EMF?
The electrical action generated by a non-electrical source, measured in volts, is referred to as emf or electromotive force. Devices, such as batteries or generators, generate an emf by converting various sources of energy into electrical energy.
The emf induced in a coil is given by
[tex]\varepsilon = \dfrac{-N \times \triangle \phi}{ \triangle t}[/tex]
where
ΔΦ is the change in magnetic flux, Δt is the change in time, and N is the number of loops.
Given that the initial magnetic flux is -58 Wb while the final magnetic flux is 38 Wb. Also, the change in time is 0.34 seconds and the number of loops is 2. Therefore, the emf induced can be written as,
[tex]\varepsilon = \dfrac{-N \times \triangle \phi}{ \triangle t}[/tex]
[tex]\varepsilon = \dfrac{-(2) \times [38-(-58)]}{0.34}\\\\\varepsilon = -564.7\rm\ V[/tex]
Hence, the emf induced in the coil is -564.7 V.
Learn more about EMF:
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