Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Percentage yield tells the percentage ratio of actual to theoretical yield. The theoretical yield of iron(III) sulfate is 26.52 g.
What is a theoretical yield?
The theoretical yield is the product formation from the complete modification of the limiting reagent in a chemical reaction.
The balanced chemical reaction is shown as,
[tex]\rm 2FePO_{4} + 3Na_{2}SO_{4} \rightarrow Fe_{2}(SO_{4})_{3} + 2Na_{3}PO_{4}[/tex]
Moles of ferric phosphate is calculated as:
[tex]\begin{aligned} \rm n &= \rm \dfrac{mass}{molar \; mass}\\\\&= \dfrac{20}{150.82}\\\\&= 0.1326\;\rm mol\end{aligned}[/tex]
From the reaction,
[tex]\dfrac{1 \;\rm mol \; Fe_{2}(SO_{4})_{3} }{2 \;\rm mol \; FePO_{4}}&= \dfrac{\rm X}{ 0.1326 \;\rm mol \; FePO_{4}}[/tex]
Solving for X:
[tex]\begin{aligned} \rm X &= (\dfrac{0.1326}{2}) \times 1 \rm \; mol\\\\&= 0.0663 \;\rm mol \;Fe_{2}(SO_{4})_{3}\end{aligned}[/tex]
Calculating mass from moles:
[tex]\begin{aligned}\rm mass &= \rm moles \times molar \rm \; mass\\\\&= 0.0663 \;\rm mol \times 399.88 \;\rm g/mol \\\\&= 26.51\;\rm g\end{aligned}[/tex]
Therefore, option A. 26.52 gm is the mass of iron(III) sulfate.
Learn more about theoretical yield here:
https://brainly.com/question/8575227
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.
