For a liter of a buffer that is 1. 5 m in acetic acid and 0. 70 m in sodium acetate, and with a result in a buffer pH of 4.01, the moles of HCl required is mathematically given as x=0.313mol
Generally, the equation for the pH is mathematically given as
pH=pKa+logsalt/acid
Generally, the equation for the Chemical Reaction is mathematically given as
HCl+CH3CooNa---->NaCl+CH3OOH
Therefore
4.01=4.74+log\frac{0.8-x}{1.3+x}
-0.52=log\frac{0.8-x}{1.3+x}
x=0.313mol
In conclusion, The moles of HCl required is
x=0.313mol
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Buffer is a solution that prevents pH variation in a solution when base or acid is added. In a liter of buffer 0.313 mol of hydrochloric acid must be added.
pH is the potential of hydrogen and is given as,
[tex]\rm pH =\rm pKa + log \dfrac{salt}{acid}[/tex]
The chemical reaction is given as,
[tex]\rm HCl+CH_{3}COONa \rightarrow NaCl+CH_{3}OOH[/tex]
Given,
pH =4.01
pKa = 4.74
Concentration of salt = 0.8 - x
Concentration of acid = 1.3 + x
Substituting values in the pH formula:
[tex]\begin{aligned} 4.01 &= 4.74 + \rm log \dfrac{(0.8 - x)}{ (1.3 + x)}\\\\-0.52 &= \rm log \dfrac{(0.8 - x)}{ (1.3 + x)}\\\\&= 0.313 \;\rm mol\end{aligned}[/tex]
Therefore, 0.313 moles of HCl are needed.
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