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At what distance does the electric field produced by a charge of -15 μc have a magnitude equal to 8. 7×104n/c?

Sagot :

Answer:

we'll use the electric field formula. ı wrote the formula in the photo.

Explanation:

The electric field formula is obtained by multiplying force and charge. When you apply this process I mentioned, you will find an electric field. then it is to write the given values and find the result. achievements.

View image alifiratkizil46

At the distance for which the electric field produced by a charge of -15 μc have a magnitude equal to 8. 7×104n/c is 3.93 meters.

What is electric force?

Electric force is the force of attraction of repulsion between two bodies.

According to the Coulombs law, the force of attraction of repulsion between charged two bodies is directly proportional to the product of charges of them and inversely proportional to the square of distance between them.

It can be given as,

[tex]F=k\dfrac{Q}{r^2}[/tex]

Here, (k) is the coulombs constant,  (Q) is the charges and (r) is the distance between the two charges.

The charge of -15 μc have a magnitude equal to 8. 7×104n/c. Put this value in the above formula,

[tex]8.7\times10^4=(8.98\times10^{9})\dfrac{15\times10^{-6}}{r^2}\\r=3.93\rm\; m[/tex]

Thus, at the distance for which the electric field produced by a charge of -15 μc have a magnitude equal to 8. 7×104n/c is 3.93 meters.

Learn more about the electric force here;

https://brainly.com/question/14372859

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