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A brass ring of diameter 10. 00 cm at 14. 3°c is heated and slipped over an aluminum rod of diameter 10. 01 cm at 14. 3°c. Assume the average coefficients of linear expansion are constant

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Temperature for combination be cooled to separate the brass ring of diameter 10.00 cm at 14.3°c and an aluminum rod of diameter 10.01 cm at 14.3°c is -204.7° C, which is not attainable.

What is linear expansion?

The linear expansion is the expansions of metal when they are heated and their length is changed along one direction.

A brass ring of diameter 10. 00 cm at 14. 3°c is heated and slipped over an aluminum rod of diameter 10. 01 cm at 14. 3°c. Assume the average coefficients of linear expansion are constant

(a) To what temperature must the combination be cooled to separate the two metals?

To find the temperature, use the following formula,

[tex]T=T_o+\dfrac{d_o^A-d_o^B}{\alpha _Ad_o^A-\alpha _Ad_o^B}[/tex]

Put the values,

[tex]T=14.3+\dfrac{10.01-10}{(19\times10^{-6})(10.01)-(24\times10^{-6})(10)}\\T=-204.7^o C[/tex]

Thus, temperature for combination be cooled to separate the brass ring of diameter 10.00 cm at 14.3°c and an aluminum rod of diameter 10.01 cm at 14.3°c is -204.7° C, which is not attainable.

Learn more about the linear expansion here;

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