Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Temperature for combination be cooled to separate the brass ring of diameter 10.00 cm at 14.3°c and an aluminum rod of diameter 10.01 cm at 14.3°c is -204.7° C, which is not attainable.
What is linear expansion?
The linear expansion is the expansions of metal when they are heated and their length is changed along one direction.
A brass ring of diameter 10. 00 cm at 14. 3°c is heated and slipped over an aluminum rod of diameter 10. 01 cm at 14. 3°c. Assume the average coefficients of linear expansion are constant
(a) To what temperature must the combination be cooled to separate the two metals?
To find the temperature, use the following formula,
[tex]T=T_o+\dfrac{d_o^A-d_o^B}{\alpha _Ad_o^A-\alpha _Ad_o^B}[/tex]
Put the values,
[tex]T=14.3+\dfrac{10.01-10}{(19\times10^{-6})(10.01)-(24\times10^{-6})(10)}\\T=-204.7^o C[/tex]
Thus, temperature for combination be cooled to separate the brass ring of diameter 10.00 cm at 14.3°c and an aluminum rod of diameter 10.01 cm at 14.3°c is -204.7° C, which is not attainable.
Learn more about the linear expansion here;
https://brainly.com/question/1217769
#SPJ4
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
