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Let dnbe the number of n-digit positive integers using only the digits 1, 2, 3, 4, 5, 6, or 7 (with repetition permitted), such that no two consecutive digits are even

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The nth term of the sequence whose integers are between 1 -7 such that there is the permission of repetition but no two consecutive digits must be even is 1.254 × 10¹¹

What are consecutive numbers?

Consecutive numbers are those numbers that succeed each other in increasing order from least to greatest. The numbers that are given:

  • 1, 2, 3, 4, 5, 6, or 7 are all consecutive.

Now, suppose a (n) denotes the number of n-digit positive integers as stated in the question, thereby using:

  • 1, 2, 3, 4, 5, 6, or 7 with the permission of repetition; no two consecutive digits are even.

Then, the number of n can be computed as n!

= (7!) × (6!) × (5!) × (4!) × (3!) × (2!) × (1!)

= 1.254 × 10¹¹

Learn more about consecutive numbers here:
https://brainly.com/question/26352026

The nth term of the series of integers is between 1 -7 such that there is the permission of repetition but no two consecutive digits must be even is 1.254 × 10¹¹

What are consecutive numbers?

Consecutive numbers are those numbers that succeed by each other in increasing order from lowest to greatest such are 1, 2, 3, 4, 5, 6, or 7.

Now, suppose n represents the number of n-digit positive integers.

1, 2, 3, 4, 5, 6, or 7 with the permission of repetition no two consecutive digits are even.

Then, the number of n can be calculated as n!

= (7!) × (6!) × (5!) × (4!) × (3!) × (2!) × (1!)

= 1.254 × 10¹¹

Learn more about consecutive numbers here:

brainly.com/question/26352026

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