Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Answer:
H3CS06
Explanation:
A chemical supply company sells sulfuric acid (H3CS06) in a concentration of 4.00 M. What volume of this solution would you need to make 12.0 mL of a 0.50 M H2SO4 s…
Molarity is the ratio of a mole of the solute of the substance to the liter of solution. The volume of solution required to make 12.0 ml of 0.50 M solution is 1.5 mL.
What is molar dilution?
Molar dilution is the calculation of the molarity or the volume of the unknown value from the known value. It is given as,
[tex]\rm M_{1}V_{1}= \rm M_{2}V_{2}[/tex]
Given,
Initial molarity = 4.00 M
Initial volume =?
Final molarity = 0.50 M
Final volume = 12.0 mL
Substituting values in the equation:
[tex]\begin{aligned} \rm V_{1} &= \rm \dfrac{\rm M_{2}V_{2}}{M_{1}}\\\\&= \dfrac{0.50 \times 12.0 }{4.00}\\\\&= 1.5 \;\rm ml\end{aligned}[/tex]
Therefore, 1.5 ml of 4.00 M sulfuric acid must be used to make 12 ml of 0.50 M solution.
Learn more about dilution and molarity here:
https://brainly.com/question/4218999
#SPJ4
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.