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Sagot :
Answer:
H3CS06
Explanation:
A chemical supply company sells sulfuric acid (H3CS06) in a concentration of 4.00 M. What volume of this solution would you need to make 12.0 mL of a 0.50 M H2SO4 s…
Molarity is the ratio of a mole of the solute of the substance to the liter of solution. The volume of solution required to make 12.0 ml of 0.50 M solution is 1.5 mL.
What is molar dilution?
Molar dilution is the calculation of the molarity or the volume of the unknown value from the known value. It is given as,
[tex]\rm M_{1}V_{1}= \rm M_{2}V_{2}[/tex]
Given,
Initial molarity = 4.00 M
Initial volume =?
Final molarity = 0.50 M
Final volume = 12.0 mL
Substituting values in the equation:
[tex]\begin{aligned} \rm V_{1} &= \rm \dfrac{\rm M_{2}V_{2}}{M_{1}}\\\\&= \dfrac{0.50 \times 12.0 }{4.00}\\\\&= 1.5 \;\rm ml\end{aligned}[/tex]
Therefore, 1.5 ml of 4.00 M sulfuric acid must be used to make 12 ml of 0.50 M solution.
Learn more about dilution and molarity here:
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