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Sagot :
The Given Data were properly outline and the relation for the quantity of heated at equilibrium was used to compute the temperature as 18.84°C
Heat Capacity
Given Data
- Mass of Copper m1 = 300g = 0.3kg
- Specific heat of copper c1 = 490Kg K
- Initial Temperature of Copper T1= 150°C
- Mass of water m2 = 4kg
- Specific heat of water = 42180 Kg K
- Initial Temperature of water T1= 20°C
At equilibrium, the final temperature of the system T2 will be same for both copper and water
McΔT(copper) = McΔT(water)
0.3*490*(T2 - 150) = 4*4180*(T2-20)
147*(T2 - 150) =16720*(T2-20)
147T2 - 22050 = 16720T2 - 334400
collect like terms
147T2 -16720T2 = - 334400+22050
147T2 -16720T2 = - 334400+22050
-16573T2 = -312350
16573T2 = 312350
Divide both sides by 16573
T2 = 312350/16573
T2 = 18.84°C
Learn more about heat capacity here:
https://brainly.com/question/21406849
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