The net torque on this system is (ml2g-ml1g)k
This refers to the type of force that causes rotation in objects which has mass and is a twisting force
Based on the complete question, we can see the given parameters:
The torque due to farther mass above the pivot is ml2gk
The torque due to nearer mass about the pivot is ml1gk
Therefore, the net torque is (ml2g-ml1g)k
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The net torque on this system in which two blocks each of mass m are attached to the ends of a massless rod, above pivot, is (ml₂g-ml_₁g)\hat k.
The torque of a body is the rate of change of angular momentum of the body. Torque is the product of moment of inertia and the angular acceleration.[tex]\tau =I\times \alpha[/tex][tex]\tau=mlg[/tex]
Here, (I) is the moment of inertia and (α) is the angular acceleration.
Two blocks each of the mass m are attached to the ends of a massless rod which pivots as shown in fig.
Initially, the rod is held in the horizontal position and then released. When, the mass was kept at farther to pivot, then the value of torque is,
[tex]\tau=ml_2g\hat k[/tex]
When, the mass was kept at nearer to pivot, then the value of torque is,
[tex]\tau=-ml_1g\hat k[/tex]
Thus, the net torque on this system above pivot is,
[tex]\tau=ml_2g\hat k+(-ml_2g\hat k)\\\tau=(ml_2g-ml_1g)\hat k[/tex]
Thus, the net torque on this system in which two blocks each of mass m are attached to the ends of a massless rod, above pivot is (ml₂g-ml_₁g)\hat k.
Learn more about the torque here;
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