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The perimeter of a rectangle is 12 meters. Find the maximum area of such a rectangle. You must support your answer with calculus; an answer without support will receive no credit

Sagot :

19nilufayesmin

Answer:

9

Step-by-step explanation:

12 divided by 4 is 3

3 multiplied by 3 is 3

The maximum area of the rectangle that has a perimeter of 12 meters would be equal to 6x - x^2.

What is the area of the rectangle?

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

Let x be the length of the rectangle and y be the width of the rectangle

The perimeter of a rectangle = 2( l + b)

                                         12   =   2(x + y)

                                         (x +y) = 6

                                             y = 6- x

The area of the rectangle = length × Width

                                          = x × y

                                          = x ( 6- x)

                                          = 6x - x^2

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