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The equilibrium for the reaction between (ch3)2nh a weak base

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pstnonsonjoku

The equilibrium for the dissolution of the weak base is ;(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH3^+(aq) + OH^-(aq)

What is a weak base?

A weak base is one that does not ionize completely in solution. As such, a weak base will have a very low base dissociation constant Kb reflecting its minimal dissociation in solution.

The question is incomplete hence we are are unable to work out the equilibrium but in solution it will look like this;

(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH3^+(aq) + OH^-(aq)

Learn more about weak base: https://brainly.com/question/4131966

mahima6824soni

The equilibrium for the reaction between (Ch₃)2NH of the weak base is (CH₃)2NH(aq) + H₂O(l) ⇄ (CH₃)2NH₃⁺(aq) + OH⁻(aq).

What are weak bases?

A weak base is one that does not completely dissociate in water.

It leaves only a small proportion of hydroxide ions and the concerned basic radical in the resulting aqueous solution.

A large proportion of dissociated base molecules.

Thus, the equilibrium for the reaction is (CH₃)2NH(aq) + H₂O(l) ⇄ (CH₃)2NH₃⁺(aq) + OH⁻(aq).

Learn more about weak bases

https://brainly.com/question/19340043

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