Answered

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A weight of 200 n is hung from a spring with a spring constant of 2500 n/m and lowered slowly. How much will the spring stretch?

Sagot :

promiseking049

8n/m this is because 200×2500 all over 100 . 0's will cancile 0's living 200×2500×1 ,25 will go into 200 8 times ×1 =8n/m

The length by which the spring got stretched will be 0.08 m. The force is directly propotional to the distance by which the spring stretched.

What is spring force?

The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is

F = kx

The given data in the problem is;

F is the spring force =200

K is the spring constant= 2500 N/m

x is the length by which spring got stretched =?

The stretch of the spring is found as;

[tex]\rm F=kx \\\\ x = \frac{F}{k} \\\\\ x= \frac{200}{2500} \\\\ x=0.08 \ m[/tex]

Hence the length by which the spring got stretched will be 0.08 m.

To learn more about the spring force refer to the link;

https://brainly.com/question/4291098

#SPJ4

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