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The magnetic field for a moving charge is the same as the magnetic field from a current element of length, dL, carrying current, I, provided that the quantity qv is replaced by 'IL'.
Magnetic force on charged particle
The magnetic force on a charged particle is determined from the product of the magnetic field strength (B), speed of the charge (v) and magnitude of the charge (q).
The magnitude of the force is caculated using the following formula;
F = qvB
Magnetic force on a current carrying element
The magnitude of the force is calculated using the following formula,
F = BILsinθ
- when the angle of inclination = 90 degrees
F = BIL
Where;
- B is the magnetic field strength
- I is current
- L is length of the wire
At equal magnetic force, the magnetic field can be calculated as follows;
B = F/qv = F/IL
Thus, the magnetic field for a moving charge is the same as the magnetic field from a current element of length, dL, carrying current, I, provided that the quantity qv is replaced by 'IL'.
Learn more about magnetic force here: https://brainly.com/question/13277365
The moving charge is the same as the field from a current element of length dl carrying current I provided that the quantity qv is replaced by "IL".
What is a magnetic field?
It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.
The magnetic force on the charged particle is found as;
[tex]\rm F = qvB[/tex]
The magnetic force on the current-carrying wire is found as;
[tex]\rm F = BIL sin \theta[/tex]
When the angle of inclination is at a right angle;
[tex]\rm F= BIL[/tex]
The magnetic field is;
[tex]\rm B = \frac{F}{qv} \\\\ B= \frac{F }{IL}[/tex]
The moving charge is the same as the field from a current element of length dl carrying current I provided that the quantity qv is replaced by "IL".
Hence the quantity qv is replaced by "IL".
To learn more about the magnetic field refer to the link;
https://brainly.com/question/19542022
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