The expression, in terms of defined quantities and g is therefore Fu =((mg/2) +2 mp) g
This can be defined as a balance or any of various other instruments or devices for weighing.
The expression in terms of defined quantities and g, for the force that the scale under left pillar shows that Fu =((mg/2) +2 mp) g .
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The expression, in terms of defined quantities and g, for the force that the scale under left pillar is (m(b)/2+2m(d))g.
Equilibrium is the location of the system, in which the system be static does not change its position with respect to time.
The image of the uniform beam which has two pillar is attached below. In this pillar,
The expression, in terms of defined quantities and g, for the force that the scale under left pillar has to be find out.
In the equilibrium position torque in left pillar is zero,
[tex]\tau_{right} =0[/tex]
It can be written as,
[tex]F_L\dfrac{L}{3}=m_bg\dfrac{L}{6}+m_dg\dfrac{2L}{3}[/tex]
[tex]F_L=\left(\dfrac{m_b}{2}+2m_d\right)g[/tex]
Thus, the expression, in terms of defined quantities and g, for the force that the scale under left pillar is (m(b)/2+2m(d))g.
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