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If a buffer is composed of 33. 80 ml of 0. 164 m acetic acid and 31. 63 ml of 0. 189 m sodium acetate, how many ml of 0. 100 m hcl can be added before the buffer capacity is reached?

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okpalawalter8

For a buffer is composed of 33. 80 ml of 0. 164 m acetic acid and 31. 63 ml of 0. 189 m sodium acetate,The volume of HCl is mathematically given as

v1=70.1148mL

What volume of  HCL can be added before the buffer capacity is reached?

Generally, the equation for the Chemical reaction is mathematically given as

HCl+CH3Coo-Na---->CH3CooH+NaCl

Therefore

Mole of HCl=34.37*0.204*10^-3

Mole of HCl=7.011*10^-{-3}

In conclusion

M1v1=m2v2

Therefore

[tex]v1=\frac{m2v2}{m1}\\\\v1=\frac{7.011*10^-{-3}}{0.1}[/tex]

v1=70.1148mL

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70.114 ml of 0. 100 m HCl can be added before the buffer capacity is reached

What is volume?

Volume is the space occupied by a three-dimensional object.

The chemical reaction is

[tex]\rm HCl+CH_3Coo-Na---- > CH_3CooH+NaCl[/tex]

step1, calculate the moles of HCl

[tex]34.37 \times0.204\times 10^-3[/tex]

[tex]\rm Moles\; of\; HCL \;7.011\times 10^{-3}[/tex]

The given Volume 1 is 33.80 ml

The given volume 2 is 31.63 ml

By the formula, [tex]M_1V_1=M_2V_2[/tex]

Putting the values in the equation

[tex]0.164 \times 33.80 = 100 \times V_2\\\\V_2 = 70.114 ml.[/tex]

Thus, the final volume is 70.114 ml.

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v1=70.1148mL

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