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Sagot :
Answer:
3 m/s
Explanation:
Initial = Final
Mass * Velocity = Mass *Velocity
8000kg * 12m/s = (8000kg+ 24000kg) * (Final Velocity)
(96000 kgm/s) / (32000kg) = (Final Velocity)
Final Velocity = 3 m/s
The speed of the coal car afterward is 3 m/s if an empty coal car of a train of mass 8000 kg is moving at 12 m/s along rails. 24000 kg of coal is dumped into the car from a motionless bin.
What is the law of conservation of momentum?
The momentum of the body before the contact is always equal to the momentum of the body after the collision, according to the law of conservation of momentum.
According to the law of conservation of momentum;
Momentum before collision =Momentum after collision
We have:
Mass of the empty coal car of train M(e) = 8000 kg
Speed V(e) = 12 m/s
Mass of the coal M(c) = 24000 kg
Let's suppose the speed of the coal car afterward V(c)
M(e) ×V(e) = (M(c)+M(e))× V(c)
8000×12 = (24000+8000)×V(c)
V(c) = 3 m/s
Thus, the speed of the coal car afterward is 3 m/s if an empty coal car of a train of mass 8000 kg is moving at 12 m/s along rails. 24000 kg of coal is dumped into the car from a motionless bin.
Learn more about the law of conservation of momentum here:
https://brainly.com/question/1113396
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