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Reagan rides on a playground roundabout with a radius of 2. 5 feet. To the nearest foot, how far does reagan travel over an angle of 4π3radians? ______ ft

Sagot :

Answer:

S = θ R      where S is the arc length and θ the arc length in radians

S = 2.5 ft * 4 π^3 rad = 2.5 * 124 = 310 ft       (1 radian = 2.5 ft)

Assuming 4π3 means 4π^3

The Reagan travel over an angle of 4π/3radians is 10.47 or 10 feet if the Reagan rides on a playground roundabout with a radius of 2. 5 feet.

What is a circle?

It is defined as the combination of points that and every point has an equal distance from a fixed point ( called the center of a circle).

We have Reagan rides on a playground roundabout with a radius of 2.5 feet.

We know the relation between arc length and radius of the circle:

S = R∅

Here R = 2.5 feet, and central angle ∅ = 4π/3

[tex]\rm S = 2.5\times \frac{4\pi}{3}[/tex]

S = 10.47 feet ≈ 10 feet

Thus, the Reagan travel over an angle of 4π/3radians is 10.47 or 10 feet if the Reagan rides on a playground roundabout with a radius of 2. 5 feet.

Learn more about circle here:

brainly.com/question/11833983

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