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Find the equation of the line through the points (0, –3) and (4, 5)

Sagot :

Answer:

y=2x-3

Step-by-step explanation:

Hi there!

We are given the points  (0, –3) and (4, 5)

We want to find the equation of the line between these points

There are 3 ways to write the equation of the line, yet the most common way is slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept

To write the equation of the line in this way, we need to first find the slope of the line
The slope can be found using the formula [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are points

We already have 2 points, but let's label their values to avoid confusion and mistakes when calculating.

m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

m=[tex]\frac{5--3}{4-0}[/tex]

Simplify

m=[tex]\frac{5+3}{4-0}[/tex]

m=[tex]\frac{8}{4}[/tex]

Divide

m=2

We found the slope of the line.

Here is the equation of the line so far:

y=2x+b

Now let's find b

As stated before, b is the y intercept of the line, which is the point where the line passes through the y axis; the value of x at the y intercept is 0

One of the points we were given (0, -3) is actually the y intercept of the line!

The value of b is the value of y at the y intercept; in this case, b is equal to -3

Now substitute -3 as b in the equation.

y=2x-3

Hope this helps!

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