For the body's position at time t is mathematically given as
s(t)=4.9t^2+5t+16
Generally, the equation for the velocity is mathematically given as
v=ds/dt
v=9.8t+5 as velocity
s=4.9t^2+5t+c
s(0)=16
16=c
s(t)=4.9t^2+5t+16
In conclusion the body's position at time t
s(t)=4.9t^2+5t+16
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The body position at the given time t is s = 4.9t² + 5t + 16 if the velocity v= ds/dt and the initial position of a body moving along a coordinate line.
A numerical representation of the distance between two items or locations is called distance. A physical length or an approximation based on other considerations in physics or common usage can be referred to as distance.
We have:
[tex]\rm v = \frac{ds}{dt}[/tex]
[tex]\rm v = 9.8t+5[/tex] is the velocity
[tex]\rm s = 4.9t^2+5t+c[/tex] is the speed
At t = 0 s(0) = 16
16 = c
[tex]\rm s = 4.9t^2+5t+16[/tex]
Thus, the body position at the given time t is s = 4.9t² + 5t + 16 if the velocity v= ds/dt and the initial position of a body moving along a coordinate line.
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