Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
The period of the given function is T = 2π
What is the period of the function?
The period T of a function f(x) is such that:
f(x + T) = f(x).
In this case, our function is:
f(θ) = e^{iθ}
Remember that this can be written as:
f(θ) = cos(θ) + i*sin(θ)
So yes, this is in did a periodic function.
Then the period of the function f(θ) is the same as the period of the cosine and sine functions, which we know is T = 2π.
If you want to learn more about periodic functions, you can read:
https://brainly.com/question/26449711
The period of the considered function f(θ) = e^{iθ} is found to be P = 2π (assuming 'i' refers to 'iota' and 'e' refers to the base of the natural logarithm)
What is euler's formula?
For any real value θ, we have:
[tex]e^{i\theta} = \cos(\theta) + i\sin(\theta)[/tex]
where 'e' is the base of the natural logarithm, and 'i' is iota, the imaginary unit.
What are periodic functions?
Functions which repeats their values after a fixed interval, are called periodic function.
For a function [tex]y = f(x)[/tex], it is called periodic with period 'T' if we have:
[tex]y = f(x) = f(x + T) \: \forall x \in D(f)[/tex]
where D(F) is the domain of the function f.
Suppose that, the period of the function [tex]f(\theta) = e^{i \theta}[/tex] be P, then we get:
[tex]f(\theta + P) = f(\theta)\\\\e^{i(\theta)} = e^{i(\theta + P)}\\\\\cos(\theta) + i\sin(\theta) = \cos(\theta + P) + i\sin(\theta + P)[/tex]
When two complex numbers are equal, then their real parts are equal and their imaginary parts are equal.
That means,
[tex]\cos(\theta) + i\sin(\theta) = \cos(\theta + P) + i\sin(\theta + P)[/tex] implies that:
[tex]\cos(\theta) = \cos(\theta + P)\\\sin(\theta) = \sin(\theta + P)[/tex]
Also, we know that the period of sine and cosine function is [tex]2\pi[/tex]
Thus, we get:
[tex]P = 2\pi[/tex]
Thus, the period of the function [tex]f(\theta) = e^{i \theta}[/tex] is P = 2π
Learn more about periodic functions here:
brainly.com/question/12529476
#SPJ4
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.
