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Malic acid, h2c4h4o5, is a diprotic acid with ka1 = 4. 0 × 10–4 and ka2 = 6. 3 × 10–6. Calculate the ph of a 0. 50 m solution of malic acid

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adioabiola

The pH of a 0.50M solution of malic acid with ka1 = 4. 0 × 10-⁴ and ka2 = 6. 3 × 10-⁶ as described is; 1.85.

pH of Diprotic acids: Malic Acid

Since, in a polyprotic acid the first hydrogen will dissociate faster than the others, If the Ka values differ by a factor of 10-³ or more, it is possible to approximately calculate the pH by using only the Ka of the first hydrogen ion.

However, the situation is different in this scenario.

On this note, the solution is as in the attached image.

Read more on Diprotic acids;

https://brainly.com/question/26015203

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mahima6824soni

The pH of a 0.50 m solution of malic acid is 1.85.

What is pH?

pH is potential hydrogen. It is the measurement of the acidity and basicity of any solution.

The ka1 = 4. 0 × 10⁻⁴

The  ka2 = 6. 3 × 10⁻⁶

The solution is 0.50 m.

First calculate the ka value

[tex]ka = \dfrac{x^2}{0.50} \\\\x^2 = 0.50 \times 4 \times 10^-^4\\\\x^2 = 2 \times 10^-^4\\x^2 = \sqrt{2 \times 10^-^4} \\\\ x = [H^+] = 1.41 \times 10^-^2[/tex]

Now, calculate the pH

[tex]pH = -log [H^+]\\\\pH = -log[ 1.41 \times 10^-2]\\\\pH = 1.85[/tex]

Thus, the pH of a 0.50 m solution of malic acid is 1.85.

Learn more about pH

https://brainly.com/question/15289741

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