Answered

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What is one time constant of a 4. 7 μf capacitor in series with a 22 kω resistor?

Sagot :

leena

Hi there!

We can solve for the time constant using the following:
[tex]\tau = RC[/tex]

τ = Time Constant (s)
R = Resistance (Ω)
C = Capacitance (F)

Simply plug in the values. Remember that:
4.7 μF = 4.7 * 10⁻ ⁶ F = 0.0000047 F

22kΩ = 22 * 10³ Ω= 22000Ω

Solve:
[tex]\tau = 0.0000047 * 22000 = \boxed{0.1034 s}[/tex]

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