Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
For a reaction rate that increases by a factor of 655 in the presence of a catalyst at 37°C, the activation energy of the new pathway is mathematically given as
Ea2=89.28JKoule/mol
What is the activation energy of the new pathway, all other factors being equal?
Generally, the equation for the rate constant is mathematically given as
K=Ae^{Ea1/Rt}
Therefore
[tex]\frac{1}{655}=\frac{1}{8.31*3.10}(Ea2-105000)[/tex]
Ea2=89286.083Joule/mol
In conclusion, the activation energy
Ea2=89.28JKoule/mol
Read more about Energy
https://brainly.com/question/13439286
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.