frankieac06
Answered

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Please Help ASAP (show work if you want its not needed i just need the answer)

Please Help ASAP Show Work If You Want Its Not Needed I Just Need The Answer class=

Sagot :

hnori22003

[tex] \cos(60) = \frac{12}{x} \\ [/tex]

[tex] \frac{1}{2} = \frac{12}{x} \\ [/tex]

[tex]x = 24[/tex]

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[tex] \sin(60) = \frac{y}{x} \\ [/tex]

[tex] \frac{ \sqrt{3} }{2} = \frac{y}{24} \\ [/tex]

[tex]y = 12 \sqrt{3} [/tex]

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