Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Step-by-step explanation:
Consider this polynomial,
[tex]8 {x}^{2} + 2x - 3[/tex]
First, I do the AC memethod. To find my two numbers,
That is to find two numbers that multiplied will equal my leading coeffeicent, A times my constant, C
And that will also add to 2, my middle term.
So using that
[tex]8 \times - 3 = - 24[/tex]
So let find factors of-24:
Factors can be positve or negative
The factors of 24 are : 1,2,3,4,6 8,12,24.
So which one of these add up to 2.
[tex]6 + ( - 4) = 2[/tex]
and
[tex]6 \times - 4 = - 24[/tex]
So six and negative four is our numbers.
Now, let set up our binomials
Step 1: Rewrite the orginal equation by using 6x and -4x instead of 2x.
Disclaimer: The placement of these numbers doesn't matter.
So we have
[tex]8 {x}^{2} + 6x - 4x - 3[/tex]
Step 2: Group the first two terms and last two terms
[tex](8 {x}^{2} + 6x) + ( - 4x - 3)[/tex]
Factors the first group by finding the GCF.
x is the greatest common variable, and 2 is the gcf so we have
[tex]2x(4x + 3) + ( - 4x - 3)[/tex]
Next, factor the next group by -1.
[tex]2x(4x + 3) - 1(4x + 3)[/tex]
Combine the outside factors.
[tex](2x - 1)(4x + 3)[/tex]
So those are the factors.
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
