The major axis, which is horizontal, is of the length [tex]2\sqrt{7.29} = 5.4[/tex] ft, the miror axis, which is vertical, is of the length [tex]2\sqrt{6.25} = 5[/tex] ft.
Suppose that the major axis is of the length 2a units, and that minor axis is of 2b units, then if major axis is on x-axis and minor axis is on y-axis, then the equation of that ellipse would be:
[tex]\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} =1[/tex]
For the considered case, the equation of the considered ellipse is:
[tex]\dfrac{x^2}{(\sqrt{7.29})^2} + \dfrac{y^2}{(\sqrt{5.4})^2} =1[/tex]
Thus, the major axis, which is horizontal, is of the length [tex]2\sqrt{7.29} = 5.4[/tex] ft,
the miror axis, which is vertical, is of the length [tex]2\sqrt{6.25} = 5[/tex] ft.
Learn more about ellipse here:
https://brainly.com/question/19910594
Answer:
The mirror has a vertical orientation and is 5.4 ft tall.
Step-by-step explanation:
Got it right. The major axis is vertical (the ellipse has a vertical orientation) because the y^2 term comes first. It is 5.4 ft tall because if you take the square root of the number under the y^2 term (square root of 7.29), it is equal to 2.7. This is only the distance from the center to one vertex on the major axis, and so twice 2.7 is 5.4, and the mirror is 5.4 ft tall.
Also I know I am weeks late, but maybe this will help others at some point. Sorry I didn't get here in time!
