Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

A car of 15 kg is traveling on a circular track. If the radius of the track is

7. 8 m and the period is 8. 5 seconds, what's the centripetal force on

the car? (Round to the nearest hundredth)

Sagot :

asuwafohjames

The magnitude of the centripetal force on the car is 69.6 N.

What is centripetal force?

This is a force acting on a body in circular path and it is directed to the center around which the body is moving.

To calculate the centripetal force on the car, we use the formula below.

Formula:

  • F = m(4π²/t²)........ equation 1

Where:

  • F = Magnitude of the centripetal force on the car,
  • m = mass of the car
  • t = time

From the question,

Given:

  • m = 15 kg
  • t = 8.5
  • π = 3.14

Substitute these values into equation 1

  • F = 15(4×3.14²/8.5²)
  • F = 69.6 N

Hence, the magnitude of the centripetal force on the car is 69.6 N.

Learn more about centripetal force here: https://brainly.com/question/20905151

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.