Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Step-by-step explanation:
Identity the variable:
Initial Velocity is 35.
Initial Height is 204
Final Height is 0.
What looking for the time.
So we have
[tex]0 = - 16 {t}^{2} + (35)t + 204[/tex]
Use Quadratic Formula,
[tex] - b± \frac{ \sqrt{b {}^{2} - 4ac} }{2a} [/tex]
A is -16, B is 35 , C is 204.
So we have
[tex] - 35± \frac{ \sqrt{ {35}^{2} - 4( - 16)(204) } }{ - 32} [/tex]
[tex] - 35± \frac{ \sqrt{1225 + 2240} }{ - 32} [/tex]
[tex] - 35± \frac{ \sqrt{3465} }{ - 32} [/tex]
[tex]{35} ± \frac{ \sqrt{3465} }{ - 32} [/tex]
The positve solution is
[tex]4.83[/tex]
So the answer is 4.83 seconds
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.