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Sagot :
The addison see to the horizon at 2 root 2mi.
We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.
We have to find the how much farther can addison see to the horizon
Which equation we get from the given condition?
[tex]d=\sqrt{\frac{3h}{2} }[/tex]
Where, we have
d- the distance they can see in thousands
h- their eye-level height in feet
For Kaylib
[tex]d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)[/tex]
For Addison h=85(1/3)
[tex]d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)[/tex]
Subtracting both distances we get
[tex]8\sqrt{2}-6\sqrt{2} =2\sqrt{2}[/tex]
Therefore, the addison see to the horizon at 2 root 2mi.
To learn more about the eye level visit:
https://brainly.com/question/1392973
Answer:
B - 2 StartRoot 2 EndRoot mi
Step-by-step explanation:
took it on edg 2022
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