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The length of one leg of an isosceles right triangle is 3 ft. what is the perimeter of the triangle? 3 3 startroot 2 endroot ft 3 3 startroot 3 endroot ft 6 3 startroot 2 endroot ft 6 3 startroot 3 endroot ft

Sagot :

The perimeter of the isosceles right angled triangle whose one leg is of 3 ft is given by: Option C: 6 + 3√2 ft


What is an isosceles right angled triangle?

It has two equal sides, and those two equal sides make 90 degrees (right angle) internally.

Referring to the figure, assuming:

  • Both equal sides are of length 'a' feet
  • The unequal side is of the length 'b' feet.

Using the Pythagoras theorem, we get:

[tex]a^2 + a^2 = b^2\\\\a = b/\sqrt{2}[/tex]

It was given that length of one of the leg is of 3 ft. Leg of an isosceles triangle refers to one of its equal sides.

Thus, we got [tex]a = 3[/tex], and therefore, we have: [tex]a = b/\sqrt{2} \implies b = a\sqrt{2} = 3\sqrt{2}[/tex]

Thus, perimeter of the triangle as:

[tex]a + a + b = 2a + b = 6 +3\sqrt{2} \: \rm ft[/tex]

Thus, the perimeter of the isosceles right angled triangle whose one leg is of 3 ft is given by: Option C: 6 + 3√2 ft

Learn more about Pythagoras theorem here:

https://brainly.com/question/12105522

Answer:

    C    :    6 + 3√2 ft

Step-by-step explanation:

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