Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
The generalization of the weighted average is the expected value of a distribution. The score that is most likely to occur is 3.
How to find the mean (expectation)?
The generalization of the weighted average is the expected value of a Probability distribution. It is given by the formula,
[tex]Mean = E(X) = \sum_{\forall x_i} f(x_i)x_i[/tex]
As we need to calculate the score that is most likely to occur, therefore, we need to calculate the expected value of the given probability distribution, therefore, the expected value can be written as,
[tex]E(x) = \sum xP[/tex]
where x is the score and P is the probability of the score occurring.
[tex]E(x) = (1 \times 0.06)+(2 \times0.20)+(3 \times 0.48)+(4 \times 26)\\\\E(x) = 2.94[/tex]
Since 2.94 is the most expected value to occur which is close to 3, therefore, the score that is most likely to occur is 3.
Also, the probability of score 3 coming is maximum which is equal to 0.48.
Hence, the score that is most likely to occur is 3.
Learn more about Expectation:
https://brainly.com/question/4515179
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
