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Why is the Area for my shape not correct and can you explain why?

Why Is The Area For My Shape Not Correct And Can You Explain Why class=

Sagot :

Starrysoul100

[tex]\bold{\huge{\underline{ Solution }}}[/tex]

Here, We have given

  • 2 squares , In which 1 square is enclosed within the another square and it arranged in a form that it forms 4 right angled triangle
  • The height and base of the given right angled triangles are 6 and 3 each.

We know that,

Area of triangle

[tex]{\sf{=}}{\sf{\dfrac{1}{2}}}{\sf{ {\times} base {\times} height }}[/tex]

Subsitute the required values,

[tex]{\sf{=}}{\sf{\dfrac{1}{2}}}{\sf{ {\times} 3 {\times} 6}}[/tex]

[tex]\sf{ = 3 {\times} 3 }[/tex]

[tex]\bold{ = 9 }[/tex]

Therefore,

Area covered by 4 right angled triangles

[tex]\sf{ = 4 {\times} 9 }[/tex]

[tex]\bold{ = 36}[/tex]

Now,

We have to find the area of the big square

  • The length of the side of the big square
  • [tex]\sf{ = 6 + 3 = 9 }[/tex]

We know that,

Area of square

[tex]\sf{ = Side {\times} Side }[/tex]

Subsitute the required values,

[tex]\sf{ = 9 {\times} 9 }[/tex]

[tex]\bold{ = 81 }[/tex]

Therefore,

The total area of shaded region

= Area of big square - Area covered by 4 right angled triangle

[tex]\sf{ = 81 - 36 }[/tex]

[tex]\bold{ = 45 }[/tex]

Hence, The total area of shaded region is 45 .

Part 2 :-

Here,

We have to find the area of non shaded region

According to the question

  • Hypotenuse = The length of square

Let the hypotenuse of the given right angled triangle be x

Therefore,

By using Pythagoras theorem,

  • This theorem states that the sum of the squares of the base and perpendicular height is equal to the square of hypotenuse.

That is,

[tex]\sf{ (Perpendicular)^{2} + (Base)^{2} = (Hypotenuse)^{2} }[/tex]

Subsitute the required values

[tex]\sf{ (6)^{2} + (3)^{2} = (x)^{2} }[/tex]

[tex]\sf{ 36 + 9 = (x)^{2} }[/tex]

[tex]\sf{ x = \sqrt{45}}[/tex]

[tex]\bold{ x = 6.7 }[/tex]

That means,

  • The length of the small square = 6.7

We know that ,

Area of square

[tex]\sf{ = Side {\times} Side }[/tex]

Subsitute the required values,

[tex]\sf{ = 6.7 {\times} 6.7 }[/tex]

[tex]\bold{ = 44.89 \:\: or \:\: 44.9 }[/tex]

Therefore ,

Area of non shaded region

= Area of big square - Area of small square

[tex]\sf{ = 81 - 44.9 }[/tex]

[tex]\bold{ = 36.1 }[/tex]

Hence, The total area of non shaded region is 36.1 or 36 (approx) .

Part 3 :-

Here, we have to

  • find the total area of the figure

Therefore,

The total area of the figure

= Non shaded region + Shaded region

[tex]\sf{= 36 + 45 }[/tex]

[tex]\bold{= 81}[/tex]

Hence, The total area of the given figure is 81 .

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