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What is the energy required to remove the electron from a hydrogen atom in the n = 11 state?

Sagot :

mickymike92

Based on the data given, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

What is ionization energy?

Ionization energy is the energy requiredto remove an electron from a neutral atom or a cation in its gaseous state.

To calculate the energy required to remove the electron from a hydrogen atom in the n = 11 state, the formula below is used:

  • [tex]E_n = \frac{E_0 × Z^{2}}{n^{2}}[/tex]

where

[tex]E_0 \: is \: ground \: state \: energy \: of \: hydrogen \: atom \: = -13.6 eV \\ [/tex]

  • Z = 1
  • n = 11

substituting the values:

[tex]E_n = \frac{ - 13.6 × 1^{2}}{11^{2}} \: = - 0.112 \: eV[/tex]

Therefore, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

Learn more about ionization energy at: https://brainly.com/question/1445179

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