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what is thecentre and diameter of the circle with equation
[tex]x {2} + {y2} - 2y + 1 = 16[/tex]
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What Is Thecentre And Diameter Of The Circle With Equation Texx 2 Y2 2y 1 16tex class=

Sagot :

Answer:

The exact value of sin 22.5° using the half-angle formula is √(2 - √2) / 2 or 0.38

Step-by-step explanation:

Let us consider θ = 22.5 º

Therefore, sin2θ =  [(1− cos 2θ) / 2] -------(1)

If θ = 22.5° then 2θ is 45°.

On substituting the value of θ in equation (1), we get

sin2 22.5° =  [(1− cos (2 × 22.5°)) / 2]

sin2 22.5° =  [(1− cos 45°) / 2]

sin2 22.5°=  [ [1 - (1 / √2)] / 2 ]

sin2 22.5°=  (2 - √2) / 4 [ on simplifying the above RHS value ]

sin 22.5° = [√(2 - √2) / 2]

After substituting the value of √2 as 1.414 in the above equation, we get

sin 22.5°= 0.38

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