Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

what is thecentre and diameter of the circle with equation
[tex]x {2} + {y2} - 2y + 1 = 16[/tex]

What Is Thecentre And Diameter Of The Circle With Equation Texx 2 Y2 2y 1 16tex class=

Sagot :

Answer:

The exact value of sin 22.5° using the half-angle formula is √(2 - √2) / 2 or 0.38

Step-by-step explanation:

Let us consider θ = 22.5 º

Therefore, sin2θ =  [(1− cos 2θ) / 2] -------(1)

If θ = 22.5° then 2θ is 45°.

On substituting the value of θ in equation (1), we get

sin2 22.5° =  [(1− cos (2 × 22.5°)) / 2]

sin2 22.5° =  [(1− cos 45°) / 2]

sin2 22.5°=  [ [1 - (1 / √2)] / 2 ]

sin2 22.5°=  (2 - √2) / 4 [ on simplifying the above RHS value ]

sin 22.5° = [√(2 - √2) / 2]

After substituting the value of √2 as 1.414 in the above equation, we get

sin 22.5°= 0.38