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Complete and balance the following half-reaction in acidic solution mno4 ---> mno2

Sagot :

batolisis

The completely balanced reaction of the half-reaction in acidic solution is ; MnO₄⁻ (aq)  + 3e⁻ + 4H⁺ ------>  MnO₂(s)  +  2H₂O(l)

Given data :

The half-reaction in acidic solution

MnO₄⁻ (aq) --> MnO₂(s)

Complete and balance the Half-reaction

Determine the oxidation number on both sides

Oxidation number of Mn in MnO₄⁻  = +7

Oxidation number of Mn in MnO₂ = +4

First step : Balance the oxidation number

MnO₄⁻ (aq)  + 3e⁻  ------ > MnO₂(s)

Next step : Balance the charge in the reaction

MnO₄⁻ (aq)  + 3e⁻ + 4H⁺ ------>  MnO₂(s)

Final step : Completely balance the half reaction

MnO₄⁻ (aq)  + 3e⁻ + 4H⁺ ------>  MnO₂(s)  +  2H₂O(l)

Hence we can conclude that The completely balanced reaction is :

MnO₄⁻ (aq)  + 3e⁻ + 4H⁺ ------>  MnO₂(s)  +  2H₂O(l)

Learn more about Balancing half-reaction : https://brainly.com/question/26263317

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