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find the horizontal asymptote for y= 5x/x+6 .
y = 0
y = −6
none
y = 5

Sagot :

semsee45

Answer:

[tex]y = 5[/tex]

Step-by-step explanation:

Given function:

[tex]y=\dfrac{5x}{x+6}[/tex]

[tex]\implies y=5 \left( \dfrac{x}{x+6}\right)[/tex]

[tex]\textsf{As }x \rightarrow +\infty, \ \dfrac{x}{x+6} \rightarrow1[/tex]  

[tex]\implies y\rightarrow5[/tex]

[tex]\textsf{As }x \rightarrow -\infty, \ \dfrac{x}{x+6} \rightarrow1[/tex]  

[tex]\implies y\rightarrow5[/tex]

As [tex]x[/tex] approaches infinity and negative infinity, [tex]y[/tex] approaches 5 (but never gets there).    Therefore, the horizontal asymptote is [tex]y=5[/tex]

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