Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

If 25 milliliter of 0. 80 m hcl is used to completely neutralize 40. Milliliters of naoh solution, what is the molarity of the base?

Sagot :

samueladesida43

If 25 milliliter of 0. 80M HCl is used to completely neutralize 40. milliliters of NaOH solution, the molarity of the base is 0.5M.

How to calculate molarity?

The molarity of a solution can be calculated using the following expression:

M1V1 = M2V2

Where;

  • M1 = molarity of acid
  • M2 = molarity of base
  • V1 = volume of acid
  • V2 = volume of base

25 × 0.80 = 40 × M2

20 = 40M2

M2 = 20/40

M2 = 0.5M

Therefore, if 25 milliliter of 0. 80M HCl is used to completely neutralize 40. milliliters of NaOH solution, the molarity of the base is 0.5M.

Learn more about molarity at: https://brainly.com/question/12127540

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.