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If 25 milliliter of 0. 80 m hcl is used to completely neutralize 40. Milliliters of naoh solution, what is the molarity of the base?

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samueladesida43

If 25 milliliter of 0. 80M HCl is used to completely neutralize 40. milliliters of NaOH solution, the molarity of the base is 0.5M.

How to calculate molarity?

The molarity of a solution can be calculated using the following expression:

M1V1 = M2V2

Where;

  • M1 = molarity of acid
  • M2 = molarity of base
  • V1 = volume of acid
  • V2 = volume of base

25 × 0.80 = 40 × M2

20 = 40M2

M2 = 20/40

M2 = 0.5M

Therefore, if 25 milliliter of 0. 80M HCl is used to completely neutralize 40. milliliters of NaOH solution, the molarity of the base is 0.5M.

Learn more about molarity at: https://brainly.com/question/12127540

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